Answer:
-1
Explanation:
if (2x-3) is a Factor of 6x² + bx-12?, we are to find the value of b.
Since 2x-3 is a factor, we will equate 2x-3 to zero and calculate the value of x.
2x-3 = 0
2x = 3
x = 3/2
Next is to substitute x = 3/2 into the quadratic equation and get b.
6x² + bx-12 = 0
6(3/2)²+3b/2-12 = 0
6(9/4)+3b/2 = 12
54/4+3b/2 = 12
(54+6b)/4 = 12
cross multiply
54+6b = 4*12
54+6b = 48
6b = 48-54
6b = -6
b = -6/6
b = -1
Hence the value of b is -1