Final answer:
The average atomic mass of boron is 10.811 amu.
Step-by-step explanation:
The average atomic mass of boron can be calculated using the percentages and masses of its isotopes. In this case, we have two isotopes of boron: ¹⁰B, which makes up 19.9% of the atoms and has a mass of 10.01294 amu, and ¹¹B, which makes up 80.1% of the atoms and has a mass of 11.00931 amu.
To calculate the average atomic mass, we multiply the mass of each isotope by its percentage abundance and then add the results:
Average atomic mass = (mass of ¹⁰B)(abundance of ¹⁰B) + (mass of ¹¹B)(abundance of ¹¹B)
= (10.01294 amu)(0.199) + (11.00931 amu)(0.801)
= 2.001 amu + 8.810 amu
= 10.811 amu
Therefore, the average atomic mass of boron is 10.811 amu.