Question

If the accepted value for the density of rubber is 1.15 g/mL, what is your percent error for each rubber

stopper?

Answer 1

4.34%

Step-by-step explanation:

The accepted value for the density of rubber is 1.15 g/mL

Let the calculated value for the density of rubber is 1.2 g/mL

We need to find the percent error for rubber stopper. It can be calculated as follows :

`\text{Error}=\frac{|\text{actual value-calculated value}|}{\text{actual value}}* 100\\\\\text{Error}=(1.15-1.2)/(1.15)* 100\\\\\text{Error}=4.34\%`

So, the percent error for the density of rubber is 4.34%.