Question

If 540.0 mL of nitrogen at 9.00 °C is heated to a temperature of 220.0 °C, what will be the new

volume of the gas?

Answer 1

943.82 ml

Step-by-step explanation:

Assuming constant pressure

V1/T1 = V2/T2

T2 * V1/T1 = V2 ( T must be in K units)

(220 + 273.15) * 540 / (273.15 + 9) = 943.8 ml