Question

A soccer ball rolls across a field with

an initial velocity of 14.9. Due to friction, it slows down at a rate of .5 until eventually coming to a stop. How far did it roll AND how long did it take to get there?​

Answer 1

The value is
`s = 222.01 \ m`

Step-by-step explanation:

From the question we are told that

The initial velocity is
`u = 14.9 \ m/s`

The deceleration is
`a = - 0.5`

Generally from kinematic equations we have that

`v^2 = u^2 + 2as`

Here v is 0 m/s because the velocity of the ball when at rest is zero so

`0^2 = 14.9^2 + 2 (-0.5)s`

=>
`s = (222.01)/(1)`

=>
`s = 222.01 \ m`