225k views
5 votes
How far from the line 3x+2y=5 is the point of intersection of x+y=5 and x–y=3?

User Big
by
5.0k points

2 Answers

5 votes
Point form:

(-5, 10)


Equation form:

X = -5, y = 10
User ObjectDB
by
4.8k points
4 votes

Answer:

d= 2.4961508830135313

Explanation:

First find the intersection of x+y=5 and x–y=3

Add the equations

x+y=5

x–y=3

----------------

2x = 8

Divide by 2

2x/2 = 8/2

x = 4

Subtract the equations

x+y=5

- x+y=-3

------------------

2y = 2

y=1

(4,1)

We need to know the distance from the line 3x+2y=5 and the point (4,1)

Rewritng the equation of the line

3x+2y -5=0

The formula for the distance is

| ax1+by1+c|

d= ------------------- where a b and c are the coefficients on the line

sqrt( a^2+b^2)

| 3*4+2*1+-5|

d= -------------------

sqrt( 3^2 +2^2)

| 12+2-5|

d= -------------------

sqrt( 9+4)

9

d= -------------------

sqrt(13)

d= 2.4961508830135313

User Catherine O
by
4.9k points