Answer:
![(1)/(19)](https://img.qammunity.org/2021/formulas/mathematics/college/gzty4dpn5rih9qxidvyj53amtj13a3i3n2.png)
Explanation:
Let's let B represent the amount of blue cubes, Y represent the amount of yellow cubes, and G represent the amount of green cubes.
We know that there are three times as many blue cubes as yellow cubes. In other words:
![B=3Y](https://img.qammunity.org/2021/formulas/mathematics/high-school/kfwl4d2xndj4k0or4o9r7o8zzuweu72btp.png)
We also know that the are as five times as many green cubes as blue cubes. So:
![G=5B](https://img.qammunity.org/2021/formulas/mathematics/high-school/y4i0ak7w8eb7xuykibks2hgu0ekinfgpxv.png)
If Sarah takes a random cube, the chance it will be a yellow cube will be the total amount of yellow cubes over the total amount of cubes. In other words:
![P=(Y)/(Y+B+G)](https://img.qammunity.org/2021/formulas/mathematics/high-school/1eh2spw1tzkr4tq8snl63cpl7nyjpuj07f.png)
We can simplify this. Let's substitute 5B for G. This yields:
![P=(Y)/(Y+B+5B)](https://img.qammunity.org/2021/formulas/mathematics/high-school/x5c9pttxfvctqx9vjtyi3x6ewuiz7guc00.png)
Combine like terms:
![P=(Y)/(Y+6B)](https://img.qammunity.org/2021/formulas/mathematics/high-school/sxt03w5r9hwwuavzhmepzccqfkrkdbeiga.png)
We can then substitute 3Y for B. This gives us:
![P=(Y)/(Y+6(3Y))](https://img.qammunity.org/2021/formulas/mathematics/high-school/i38o42x98ex1zs0wqm1uumshvklvlmos7e.png)
Multiply:
![P=(Y)/(Y+18Y)](https://img.qammunity.org/2021/formulas/mathematics/high-school/uqnjd10n0ck21k9rl1v9m9jcspfv5z8sm0.png)
Again, add:
![P=(Y)/(19Y)](https://img.qammunity.org/2021/formulas/mathematics/high-school/v7796p6yl4qx4n3qq0mqinpuvbld561cr4.png)
We can now cancel out the Y:
![P=(1)/(19)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mxmi0qe4n0m5nmhm8hz8hk6j6hjuhp2hsj.png)
So, the chance of Sarah picking out a yellow cube is 1/19 or about 5.3% chance.
And we're done!