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Please do step by steps for each!

#1) Find the polynomial with roots at 2 and 6

#2) Find the polynomial with a double root at -3 and another root at 4

#3) Find the polynomial with roots 0, -3 and 5

1 Answer

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Answer:

  • x² - 8x + 12
  • x³ + 2x² - 15x - 36
  • x³ -2x² - 15x

Explanation:

#1) Find the polynomial with roots at 2 and 6

  • (x -2)(x - 6) = x² - 8x + 12

#2) Find the polynomial with a double root at -3 and another root at 4

  • (x+3)(x+3)(x-4) = (x²+6x+9)(x-4) = x³ + 2x² - 15x - 36

#3) Find the polynomial with roots 0, -3 and 5

  • (x -0)(x+3)(x-5) = x(x²-2x - 15) = x³ -2x² - 15x
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