Question

Compute for the pH of 0.415 M HCl acid.​

Answer 1

The answer is

0.38

Step-by-step explanation:

HCL is a strong acid and therefore undergo complete dissociation

We have

`HCL \rarr H^( + ) \: + \: Cl^( - )`

The concentration of Hydrogen ion is also 0.415 M

The pH of a solution can be found by using the formula

`pH = - log( {H }^( + ) )`

So we have

`pH = - log(0.415) \\ = 0.381951903...`

We have the final answer as

0.38

Hope this helps you