If x - y = 12 √(xy ) = 3 find the valve of {x }^(2) + {y}^(2) ​

Question

If


`x - y = 12`

`√(xy ) = 3`
find the valve of

`{x }^(2) + {y}^(2)`
​

Answer 1

Given :

→x-y=12

→xy= 3²

=9

Equation formed:

`{(x - y)}^(2) = {x}^(2) + {y}^(2) - 2xy`

Step by step explanation:

`{(12)}^(2) = {x}^(2) + {y}^(2) - 2 * 9 \\ 144 + 18 = {x}^(2) + {y}^(2) \\ = 162`

hope it helped you:)