If x - y = 12 √(xy ) = 3 find the valve of {x }^(2) + {y}^(2)

asked Jul 3, 2021 233k views

3 votes

find the valve of

${x }^(2) + {y}^(2)$

$If x - y = 12 √(xy ) = 3 find the valve of {x }^(2) + {y}^(2) -example-1$

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3 votes

Answer:

Given :

→x-y=12

→xy= 3²

Equation formed:

${(x - y)}^(2) = {x}^(2) + {y}^(2) - 2xy$

Step by step explanation:

${(12)}^(2) = {x}^(2) + {y}^(2) - 2 * 9 \\ 144 + 18 = {x}^(2) + {y}^(2) \\ = 162$

hope it helped you:)

Ivona Tau answered Jul 8, 2021

3.8k points

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