Question

Plz solve this if u know plz​

Answer 1

- 3

Explanation:

Using the rules of exponents/ radicals

`a^{(m)/(n) }` ⇔
`\sqrt[n]{a^(m) }`

`a^(-m)` ⇔
`(1)/(a^(m) )`

Thus

`64^{(1)/(3) }` =
`\sqrt[3]{64}` = 4

`64^{-(1)/(3) }` =
`(1)/(4)`

`64^{(2)/(3) }` =
`\sqrt[3]{64^(2) }` = 4² = 16

Substituting values into the given expression

`(1)/(4)` (4 - 16)

=
`(1)/(4)` × - 12

= - 3

Answer 2

`{64}^{ - (1)/(3) } ( {64}^{ (1)/(3) } - {64}^{ (2)/(3) } ) \\ {64}^{ (1)/(3) - (1)/(3) } - {64}^{ (2)/(3) - (1)/(3) } \\ {64}^(0) - {64}^{ (1)/(3) } \\ 1 - \sqrt[3]{64} \\ 1 - 4 \\ - 3`

Answer:

`- 3`