Answer:
f(g(3)) = 56
g(f(3)) = 25
Explanation:
fog = f(2x+1)
f(2x+1) = (2x+1)^2 + 2x+1
(2x+1)^2 + 2x+1 = 4x^2+6x+2
f(g(x)) = 4x^2+6x+2
f(g(3)) = 4(3)^2+6(3)+2
f(g(3)) = 56
gof = g(x^2+x)
g(x^2+x) = 2(x^2+x)+1
2(x^2+x)+1 = 2x^2 + 2x + 1
g(f(x)) = 2x^2 + 2x + 1
g(f(3)) = 2(3)^2 + 2(3) + 1
g(f(3)) = 25