Question

(4•6/2)v+10=4^3v+10 solve

Answer 1

(4•6/2)v + 10 = 4^3v + 10

(24/2)v + 10 = 4^3v + 10

12v + 10 = 64v + 10

-12v -12v

10 = 52v + 10

-10 -10

0 = 52v

/52 /52

V= 0

Answer 2

v=0

Explanation:

Solve what is in the parentheses, then the exponents: 12v+10=64v+10

Subtract 64v from both sides: -52v+10=10

Subtract 10 from both sides: -52v=0

Divide by -52: v=0