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A 58.9 g piece of aluminum, with density of 2.70 g/cm3, is added to a graduated cylinder with a volume of 25.2 mL of water. What is the final volume of water in the graduated cylinder?
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A 58.9 g piece of aluminum, with density of 2.70 g/cm3, is added to a graduated cylinder with a volume of 25.2 mL of water. What is the final volume of water in the graduated cylinder?

User NYRecursion
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1 Answer

0 votes

Answer:

47.0 mL

Step-by-step explanation:

You need to find the volume of the piece of aluminum. Use the density.

(58.9 g)/(2.70 g/cm³) = 21.8 cm³ = 21.8 mL

Now that you have the volume of the aluminum, add it to the volume of water.

25.2 mL + 21.8 mL = 47.0 mL

The final volume will be 47.0 mL.

User Eddie Parker
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4.7k points
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