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Which is the equation of a circle with a radius of 3 and a center at (0, 0) A . x ^ 2 + y ^ 2 = 3 B x ^ 2 + y ^ 2 = 6; x ^ 2 + y ^ 2 = 9 D. (x - 3) ^ 2 + (y - 3) ^ 2 = 0; (x + 3) ^ 2 + (y + 3) ^ 2 = 0

1 Answer

6 votes

Answer:

x² + y² = 9

Step-by-step explanation:

circle formula: (x -h)² + (y - k)² = r²

where (h, k) is the center, r is radius

Here given for center: (0, 0)

Identify

  • h = 0
  • k = 0
  • r = 3

Equation of circle:

  • (x - 0)² + (y - 0)² = 3²
  • x² + y² = 9
User Vbarbarosh
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