Answer:
let the numbers be x and y.
x+y=133......(i)
x-y=49.......(ii)
solving eqn (i) and (ii) we get,
x+y=133
x-y=49
we solved it through elimination method.
Here, y and y cancelled out so, we've,
or, 2x=182
so, x=91
now putting value of x in any of the eqn.
in eqn(i)
or, x+y=133
or, 91+y=133
or, y=133-91
so, y=42
Therefore, the two numbers are 91 and 42.
Thank you.