The accepted value for the mass of a moonrock is 46.37 g. In an experiment the rock is measured to be 47.25 g. What is the percent error of the measurement?

Question

asked Feb 23, 2021 166k views

1 Answer

Will Neithan · Answer 1 · 2021-02-27T08:04:00+0000

Answer:

The answer is

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = (error)/(actual \: \: number) * 100\% \\$

From the question

actual measurement = 46.37 g

error = 47.25 - 46.37 = 0.88

The percentage error of the measurement is

$P(\%) = (0.88)/(46.37) * 100 \\ = 1.89777873...$

We have the final answer as

Hope this helps you