Answer:
150 N right
Step-by-step explanation:
Let's say up is +y, down is -y, right is +x, and left is -x.
F₁ = 150 N
F₂ = -150 N
F₃ = 150 N
The net force in the y direction is:
Fnet,y = F₁ + F₂
Fnet,y = 150 N − 150 N
Fnet,y = 0 N
The net force in the x direction is:
Fnet,x = F₃
Fnet,x = 150 N
Therefore, the overall net force is 150 N to the right.
The net force is unbalanced and the motion is changing.