Question

How many moles of solute are in 125 mL of a 2.0 M hydrochloric acid (HCI) solution?

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Answer 1

`~~~~~~w = (SVM)/(1000)\\\\\\\implies nM = (SVM)/(1000)\\\\\\\implies n= (SV)/(1000)\\\\\\\implies n = \frac{125 ~ \text{mL}* 2.0~ \text{M}}{1000}\\\\\\\implies n = (250)/(1000)\\\\\\\implies n = 0.25~ \text{mol.}\\\\\text{The number of moles is 0.25.}`

Answer 2

`\sf\large \green{\underbrace{\red{Answer⋆}}}:`

0.250 moles

Step-by-step explanation:

First we will convert quantity of solution into liters

`\implies \sf 125 \: ml * {10}^( - 3) = 0.125 \: l`

Now we will use morality formula

`\sf molarity = (no \: of \: moles)/(volume) \\ \\ \sf no \: of \: moles = molarity * volume`

Here volume(quantity) = 0.125 l

AND no. of moles(given) = 2.0M

`\sf \implies no \: of \: moles = 2 * 0.125 \\ \\ \sf \implies no \: of \: moles = 0.250 \: moles \: of \: HCl`