Question

A car traveling 29 mi/h accelerates uniforml for 8.5 s, covering 471 ft in this time.

What was its acceleration? and What is the final velocity at this time?
I know the acceleration is 3.01 ft/s^2 i just need the final velocity in ft/s

Answer 1

Step-by-step explanation:

We know that :

u = 29 mph = 12.96 m/s

a = 3.01 ft/s^2 = 0.92 m/sec^2

t = 8.5sec

v = u + at

V = 12.96 + 0.92 * 8.5

v( final velocity) = 20.78 m/s = 68.17 ft/s

Answer 2

68.12 ft/s

Step-by-step explanation:

assuming that the acceleration is correct

Given

a = 3.01 ft/s²

time elapsed, t = 8.5s

initial velocity, u = 29 mi/h = 42.533 ft/s

final velocity, v = we are asked to find this

recall that one of the equations of motions can be expressed as:

v = u + at, where v, u, a and t are defined as above

simply substitute the known values above into the equation;

v = u + at

v = 42.533 + (3.01)(8.5)

v = 68.12 ft/s