Question

A train travels with a constant speed of 20.0m/s for 7.00s. Determine all

unknowns and answer the following question(s).
What is the magnitude of the train's acceleration?

Answer 1

The magnitude of the train's acceleration is 2.86 m/s².

Step-by-step explanation:

The magnitude of the train's acceleration can be determined by using the following equation:

acceleration = (final velocity - initial velocity) / time

In this case, the train's initial velocity is 0 m/s (since it starts at rest) and its final velocity is 20.0 m/s. The time taken is 7.00 seconds. Plugging in these values into the equation, we get:

acceleration = (20.0 m/s - 0 m/s) / 7.00 s = 2.86 m/s²

Therefore, the magnitude of the train's acceleration is 2.86 m/s².

Answer 2

acceleration is zero m/s²

Step-by-step explanation:

It is given that the train travels at constant speed (i.e speed does not change)

If speed does not change, then the train is neither accelerating or decelerating (i.e acceleration is zero)