Question

what is the acceleration of a ball traveling horizontally wit an initial velocity of 20 meters/seconds and, 2.0 seconds later, a velocity of 30 meters/seconds

Answer 1

`a=5\ m/s^2`

Step-by-step explanation:

Given that,

Initial velocity of the ball, u = 20 m/s

Final velocity, v = 30 m/s

Time, t = 2 seconds

Let us assume to find the acceleration of the ball. The rate at which the velocity of the ball is changing is called the acceleration of the ball. So,

`a=(v-u)/(t)\\\\a=(30-20)/(2)\\\\a=5\ m/s^2`

So, the acceleration of the ball is
`5\ m/s^2`