Question

What is the concentration (molarity) of a solution created by dissolving 81.1 grams of Mg3P2 to create a 2.5 solution?

Answer 1

The concentration of Mg3P2 solution = 0.24mol/L

Step-by-step explanation:

Mass = 81.1g

Volume = 2.5L

Concentration (C) of a solution =
`(Moles (n))/(Volume (V))`

but moles =
`(mass)/(Molar mass)` and Molar mass of Mg3P2 = 134.88g/mol

Moles =
`(81.1g)/(134.88g/mol)`

= 0.60mol

hence the concentration can be calculated by;

C =
`(0.60mol)/(2.5L) \\`

= 0.24mol/L or 0.24M