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An atom emits a photon with energy 7.13 electronvolts (eV). What is the wavelength of the photon?

a. 279 nm
b. 174 nm
c. 114 nm
d. 108 nm​

1 Answer

6 votes

Answer:

Option (b) "174 nm"

Step-by-step explanation:

Energy of emitted photon is 7.13 eV.

We need to find the wavelength of the photon.

1 eV = 1.6 × 10⁻¹⁹ J

Energy of a photon is given by :


E=(hc)/(\lambda)

Where,
\lambda is wavelength of the photon

Putting all the values,


\lambda=(hc)/(E)\\\\\lambda=(6.63* 10^(-34)* 3* 10^8)/(7.13* 1.6* 10^(-19))\\\\\lambda=1.74* 10^(-7)\ m\\\\\text{or}\\\\\lambda=174\ nm

So, the wavelength of the photon is 174 nm.

User Hendrra
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