Answer:
Numerator.
Explanation:
(2a¯⁵b²/ab³)¯³
To know if the constant term will be in the numerator or denominator, let us simplify the expression. This can be obtained as follow:
(2a¯⁵b²/ab³)¯³
Recall
m¯ⁿ = 1/mⁿ
Therefore,
(2a¯⁵b²/ab³)¯³ = 1/(2a¯⁵b²/ab³)³
= 1 ÷ (2a¯⁵b²/ab³)³
= 1 × (ab³ / 2a¯⁵b²)³
= (ab³ / 2a¯⁵b²)³
Recall
(mⁿ)ˣ = mⁿˣ
Therefore,
(ab³ / 2a¯⁵b²)³ = a³b⁹ / 2³a¯¹⁵b⁶
Recall
x^m ÷ x^n = x^(m–n)
Therefore,
a³b⁹ / 2³a¯¹⁵b⁶ = a^(3 - - 15)b^(9-6)/2³
= a^(3 +15) b^(9-6)/2³
= a¹⁸b³/2³
Thus,
(2a¯⁵b²/ab³)¯³ = a¹⁸b³/2³
From the above illustration, we can see that the constant term (i.e 'a' and 'b') are in the numerator.