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Jamie needs to build a fence around his garden , as illustrated by polygon ABCDEF on the coordinate grid below.If each unit represents one yard, what is the total length of Jamie’s fence in yards ?

A.20 yards
B.23 yards
C.26 yards
D.45 yards

Jamie needs to build a fence around his garden , as illustrated by polygon ABCDEF-example-1

1 Answer

2 votes

Answer:

C. 26 yards

Explanation:

Total length of Jamie's fence = sum of all distances from one vertex of the polygon to another = AB + BC + CD + DE + EF + FA

Use the distance formula,
d = √((x_2 - x_1)^2 + (y_2 - y_1)^2), to find the distance between vertexes.

Distance between A(-5, 5) and B(0, 5)

Let,


A(-5, 5) = (x_1, y_1)


B(0, 5) = (x_2, y_2)


AB = √((0 -(-5))^2 + (5 - 5)^2)


AB = √((5)^2 + (0)^2)


AB = √(25 + 0) = √(25)


AB = 5

Distance between B(0, 5) and C(4, 2)

Let,


B(0, 5) = (x_1, y_1)


C(4, 2) = (x_2, y_2)


BC = √((4 - 0)^2 + (2 - 5)^2)


BC = √((4)^2 + (-3)^2)


BC = √(16 + 9) = √(25)


BC = 5

Distance between C(4, 2) and D(1, -2)

Let,


C(4, 2) = (x_1, y_1)


D(1, -2) = (x_2, y_2)


CD = √((1 - 4)^2 + (-2 - 2)^2)


CD = √((-3)^2 + (-4)^2)


CD = √(9 + 16) = √(25)


CD = 5

Distance between D(1, -2) and E(-2, -2)

Let,


D(1, -2) = (x_1, y_1)


E(-2, -2) = (x_2, y_2)


DE = √((-2 - 1)^2 + (-2 -(-2))^2)


DE = √((-3)^2 + (0)^2)


DE = √(9 + 0) = √(9)


DE = 3

Distance between E(-2, -2) and F(-5, 2)

Let,


E(-2, -2) = (x_1, y_1)


F(-5, 2) = (x_2, y_2)


EF = √((-5 -(-2))^2 + (2 -(-2))^2)


EF = √((-3)^2 + (4)^2)


EF = √(9 + 16) = √(25)


EF = 5

Distance between A(-5, 5) and F(-5, 2)

Let,


A(-5, 5) = (x_1, y_1)


F(-5, 2) = (x_2, y_2)


FA = √((-5 -(-5))^2 + (2 - 5)^2)


FA = √((0)^2 + (-3)^2)


FA = √(0 + 9) = √(9)


FA = 3

Total length of Jamie's fence in yards = 5 + 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

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