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The perimeter of a rectangular garden is 290 feet. If the width of the garden is 62 feet, what is its length?

The perimeter of a rectangular garden is 290 feet. If the width of the garden is 62 feet-example-1
User Max Xu
by
6.6k points

2 Answers

5 votes

Answer:

83

Explanation:

P =290

Semiperimetru =290 :2 =145

w=62

L+62 =145

L=145 - 62

L=83

User Oroom
by
6.5k points
1 vote

Answer:

83

Explanation:

Remember that the perimeter of a rectangle is two times the width plus two times the length. In other words:

2W + 2L = P

We know that the perimeter is 290 and the width is 62. We can plug these into the equation and solve for L.

2(62) + 2L = 290

124 + 2L = 290

Subtract 124 from both sides.

2L = 166

Divide both sides by 2.

L = 83

So now we know that the length is 83 feet.

I hope you find my answer and explanation to be helpful. Happy studying.

User Mehrdad Kamelzadeh
by
5.9k points
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