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Rationalize the denominator 5√3+3√5 / 5√3- 3√5​

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Answer:


((5\, √(3) +3\,√(5))^2 )/(30 )

Explanation:

We recall that in order to rationalize this type of denominator, we can use the multiplication (in numerator and denominator) by the denominator's conjugate:


(5\, √(3) +3\,√(5) )/(5\, √(3) -3\,√(5) ) =(5\, √(3) +3\,√(5) )/(5\, √(3) -3\,√(5) )*(5\, √(3) +3\,√(5) )/(5\, √(3) +3\,√(5) )=\\=((5\, √(3) +3\,√(5))^2 )/((5\, √(3) )^2-(3\,√(5))^2 )=((5\, √(3) +3\,√(5))^2 )/((25*3)-(9*5) )=\\=((5\, √(3) +3\,√(5))^2 )/(30 )

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