Question

Sucrose: density = 1.59 g/cm³. Your experiment showed a density of 1.68 g/cm³. What is the percent error *

Answer 1

The answer is

5.66 %

Step-by-step explanation:

The percentage error of the density can be found by using the formula

`Percentage \: \: error(\%) = (error)/(actual \: \: number) * 100 \\`

From the question

actual density = 1.59 g/cm³

error = 1.68 - 1.59 = 0.09

The percentage error is

`P(\%) = (0.09)/(1.59) * 100\% \\ = 5.66037735...`

We have the final answer as

5.66 %

Hope this helps you