Question

Write an equation of the line that passes through point (-1, 5) and has the slope m = 4.

y =
9

Answer 1

The equation of the line passing through the point (-1, 5) with a slope of 4 is y = 4x + 9.

How to write the equation of a line?

The equation of a line in slope-intercept form (y = mx + b) can be written using the slope (m) and a point on the line
`(x_1, y_1)` as follows:

`y - y_1 = m(x - x_1)`

For the given point (-1, 5) and slope m = 4:

y - 5 = 4(x - (-1))

Simplify:

y - 5 = 4(x + 1)

Distribute 4:

y - 5 = 4x + 4

Add 5 to both sides:

y = 4x + 9

Therefore, the equation of the line is y = 4x + 9.

Answer 2

You want to find the equation for a line that passes through the point (-1,5) and has a slope of 4.
First of all, remember what the equation of a line is:

y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was 4. So you can right away fill in the equation for a line somewhat to read:
y=4x+b.
Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:
(-1,5). When x of the line is -1, y of the line must be 5.