Answer:
Q'(1, -4)
R'(1, -3)
S'(0, 4)
T'(0, -5)
Explanation:
If A is the X-coordinate of a pre-image point, and B is the X-coordinate of the image, then we want 4 to be the midpoint of those values. That is ...
(A + B)/2 = 4
A + B = 8 . . . . . multiply by 2
B = 8 - A . . . . . subtract A
So, the reflection over x=4 is the transformation ...
(x, y) ⇒ (8 -x, y)
The y-value stays the same, and the new x-value is the result of subtracting the x-coordinate from 8.
The given points have two different x-coordinates: 7, and 8. The corresponding image coordinates are 8-7 = 1 and 8-8 = 0.
Your points are ...
Q'(1, -4)
R'(1, -3)
S'(0, 4)
T'(0, -5)