Question

QUESTION 8 A motorboat leaves a harbor and travels at an average speed of 6 mph towards a small island. Two hours later, a cabin cruiser leaves the same harbor at an average speed of 12 mph toward the same island In how many hours after the cabin cruiser leaves the harbor will it be alongside the motorboat?

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Answer 1

2 hours

Explanation:

Distance = rate × time

That is,

d=rt

Let

t = time (hours) cabin cruiser traveled

t + 2 = time (hours) motorboat traveled

motorboat = 6 mph

Cabin cruiser =12 mph

Motorboat distance

d=rt

d = 6(t + 2)

Cabin cruiser distance

d=rt

d = 12(t)

Equates the two distance

6(t + 2) = 12t

Open bracket

6t + 12 = 12t

12 = 12t - 6t

12 = 6t

Divide both sides by 6

t = 12 / 6

= 2

t = 2 hours

The cabin cruiser will be alongside the motorboat in 2 hours