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(0,-8) and (3,-2) find the distance between each pair of points

User Savpek
by
4.9k points

1 Answer

2 votes

Answer:

The distance between the points is 6.71 unit

Step-by-step explanation:

Given points;

(0,-8) and (3,-2)

The distance between the points is given by;


d = √((x_2-x_1)^2 + (y_2-y_1)^2)

where;

x₁ = 0, x₂ = 3

y₁ = -8, y₂ = -2


d = √((x_2-x_1)^2 + (y_2-y_1)^2) \\\\d = √((3-0)^2 + (-2-(-8))^2) \\\\d = √((3^2) \ + (-2+8)^2)\\\\ d = √(3^2 +6^2 ) \\\\d = √(45) \\\\d = 6.71 \ unit

Therefore, the distance between the points is 6.71 unit

User Mirek Michalak
by
4.2k points