Question

What acceleration would a 18 kg box have if we pushed it with a force of 250 N across a surface that

has a coefficient of friction of 0.8?
N

Answer 1

`a=0.08\ m/s^2`

Step-by-step explanation:

Given that,

Mass of a box, m = 18 kg

It is pushed with a force of 250 N

The coefficient of friction is 0.8

We need to find the acceleration of the box.

Normal force acting on the box,

N = mg

M = 18 × 10

N = 180 N

The force acting on the force in terms of coefficient of friction is given by :

`F=\mu mg\\\\\text{or}\\\\ ma=\mu mg\\\\a=(\mu )/(g)\\\\a=(0.8)/(10)\\\\a=0.08\ m/s^2`

So, the acceleration of the box is
`0.08\ m/s^2`