Question

R= m/2 (c + K) for k

Answer 1

`\bold{K=\frac{2r}m-c=\frac{2r-cm}m}`

Explanation:

`\bold{r= \frac m2 (c + K)}\\^(/\frac m2)\qquad^(/\frac m2)\\ \bold{r\cdot\frac2m=c+K}\\{}\ ^(-c)\qquad^(-c)\\\bold{\frac{2r}m-c=K}`

Or if you mean r= m/[2(c + K)]

`\bold{\quad r\ =\ \frac m{ 2(c + K)}}\\^(\cdot(c+K))\quad^(\cdot(c+K))\\ \bold{r(c+K)=\frac m2}\\{}\qquad ^(/ r)\qquad^(/ r)\\\bold{c+K=\frac m2\cdot\frac1r}\\{}\quad^(-c)\qquad^(-c)\\\bold{K=\frac m{2r}-c}`