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An estate agent has three houses for sale. The prices of the houses were
in the ratio 6:4:3 and the cheapest house was priced at $240 000. What
were the prices of the other two houses? (SHOW WORKING)​

desperate need of helppp

1 Answer

3 votes

Answer:

Cost of the first house : $480,000

Cost of the second house : $320,000

Explanation:

An estate agent has three houses for sale. The prices of the houses were

in the ratio 6:4:3 and the cheapest house was priced at $240 000. What

were the prices of the other two houses? (SHOW WORKING)​

The prices of the house has a ratio of

6:4:3

Sum total = 6 + 4 + 3 = 13

Cheapest house = $240,000

The sum total cost of the 3 houses = x

x is calculated as:

= 3/13 × x =$ 240,000

= 3x = $240,000 × 13

x = $240,000 × 13/3

x = $1,040,000

The Cost of the first house =

6/13 × $1,040,000

= $480,000

Cost of the second house

= 4/13 × $1,040,000

=$320,000

Therefore,

Cost of the first house : $480,000

Cost of the second house : $320,000

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