Answer:
B. The square's side length is between 5 and 6.
Explanation:
We are given a square with vertices
A(0,0), B(5,2), C(3,7), and D (-2,5)
We solve using the Formula
√(x2 - x1)² + (y2 - y1)²
Where we have (x1, y1) and (x2, y2)
For AB
A(0,0), B(5,2)
= √(5 -0)² + (2 - 0)²
= √5² + 2²
= √25 + 4
= √29
= 5.3851648071
For BC
B(5,2), C(3,7),
= √(3 - 5)² + (7 - 2)²
= √-2² + 5²
= √4 + 25
= √29
= 5.3851648071
For A D
A(0,0),D (-2,5)
√(-2- 0)² + (5 - 0)²
= √-2² + 5²
= √4 + 25
= √29
= √5.3851648071
For CD
C(3,7), D (-2,5)
√(-2 - 3)² + (5 - 7)²
= √-5² + -2²
= √25 + 4
= √29
= 5.3851648071
The lengths of the sides of the square is equal to each other.
Therefore, the statement that is true about this square is option
B. The square's side length is between 5 and 6.