Answer:
Explanation:
Let the equation of the line passing through a point (x', y') and slope 'm' is,
y - y' = m(x - x')
Since x-value increases by 3,
Δx = 3
And y-value decreases by 2,
Δy = -2
Therefore, slope =
![(\triangle y)/(\triangle x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qvcluhb9k1uu9mkdiaeihnduqdigmz7l8k.png)
Slope =
![-(2)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9b735wr1uu4p8fxc1vii1igfgpgrg7hpoy.png)
Equation of the line passing through (-2, 5) and slope =
will be,
y - 5 =
![-(2)/(3)(x+2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gg43rb5rar56fkzwvzjowbevsdhph87988.png)
y =
![-(2)/(3)x-(4)/(3)+5](https://img.qammunity.org/2021/formulas/mathematics/high-school/x13tw9qnilseau1qdkznd82hinnghni1e0.png)
y =
![-(2)/(3)x+(11)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/txwdvox6vblk1condzg44rcc2loywsqh08.png)
y =
![(1)/(3)(-2x+11)](https://img.qammunity.org/2021/formulas/mathematics/high-school/mw91wumjt2w4m655dtre758uqeanj2s7my.png)
Table for input-output values will be,
x -2 0 1 2 3
y 5 3.7 3 2.3 1.7
We can plot these points to get the line on a graph.