Question

6t−20−32u6, t, minus, 20, minus, 32, u when

t

=

6

t=6t, equals, 6 and

u

=

1

4

u=

4

1

​

u, equals, start fraction, 1, divided by, 4, end fraction.

Answer 1

The expression is equal to 8

Explanation:

This is the question in proper

6t−20−32u

When u= 1/4 t= 6

We were given this, 6t−20−32u then we were given the value of u= 1/4 and that of t= 6.

All we need here is to substitute u= 1/4 t= 6 into 6t−20−32u then evaluate it as follows

6(6)-20-32(1/4)

6×6=36

32×(1/4)=8

Then merge it together and calculate it we have

=36-20-8=8