Question

A tennis ball is released at rest from the top of the school. It hits the ground after falling for 2.00 s. What was the height from which the ball was dropped?

a 15.4 m
b 9.8 m
c 19.6 m
d 20.7 m

Answer 1

`\huge\boxed{\sf h = 19.6\ m}`

Step-by-step explanation:

Given:

Time = t = 2.00 secs

Acceleration due to gravity = g = 9.8 m/s²

Initial Velocity =
`\sf V_(i)` = 0 m/s

Required:

Height = h = ?

Formula:

`\sf h = V_(i) t + (1)/(2) gt^2`

Solution:

Putting the given in the above formula

h = (0)(2) + 1/2 (9.8)(2)²

h = 1/2 (9.8)(4)

h = (9.8)(2)

h = 19.6 m

Hope this helped!

~AnonymousHelper1807