Question

7)

Factor: 27a3 + 64b3
A)
(3a + 4b)(9a2 + 12ab + 16b2)
as
B)
(3a + 4b)(922 - 12ab + 16b2)
ght
(3a - 4b)(9a2 + 12ab + 1662)
ning
D)
(3a - 4b)(9a2 + 12ab - 1662)
-50
bols

Answer 1

B

Explanation:

a³ + b³ = (a + b)(a² -ab + b²)

27 = 3* 3 * 3 = 3³

64 = 4 * 4 * 4 = 4³

27a³ + 64b³ = 3³a³ + 4³b³

= (3a)³ + (4b)³

= (3a + 4b) ( [3a]² - 3a*4b + [4b]²)

= (3a + 4b) (9a² - 12ab + 16b²)