Question

if a quadratic has a Vertex at (-2, 2) and passes through (-1, 0) what is the equation in standard form?

Answer 1

• y = -2x² - 8x - 6

Explanation:

The equation in the vertex form is:

• y = a(x -h)² + k

(h, k) is coordinates of the vertex and is given as (-2, 2)

• (h, k) = (-2, 2)
• y= a(x + 2)² + 2

Using the point (-1, 0), we find the value of a;

• 0 = a(-1 + 2)² + 2
• a = -2

So the function is:

• y = -2(x + 2)² + 2

And in standard form:

• y = -2x² - 8x - 8 + 2
• y = -2x² - 8x - 6