Question

7. There are 80 houses in a neighborhood.

• Company X provides electricity to one eighth of the
houses.
• Company Y provides electricity to two fifths of the
houses.
Company Z provides electricity to the
remaining houses.
In this neighborhood, Company Z provides electricity
to how many houses?

Answer 1

Company Z provides electricity to 38 houses in the neighborhood.

Step-by-step explanation:

To find out how many houses Company Z provides electricity to in the neighborhood, we need to first calculate the number of houses that Company X and Company Y provide electricity to. Company X provides electricity to one-eighth of the houses, which is 80 / 8 = 10 houses. Company Y provides electricity to two-fifths of the houses, which is 80 * 2/5 = 32 houses. Now, we can calculate the number of houses that Company Z provides electricity to by subtracting the houses serviced by Company X and Company Y from the total number of houses in the neighborhood. So, 80 - 10 - 32 = 38 houses. Therefore, Company Z provides electricity to 38 houses in the neighborhood.

Answer 2

j is the answer because 1/8 of the houses is 5 2/5 of 40 is 16 and 16 +5 =21 40-21 =19

Step-by-step explanation: There are 80 houses in a neighborhood.

• Company X provides electricity to one eighth of the

houses.

• Company Y provides electricity to two fifths of the

houses.

Company Z provides electricity to the

remaining houses.

In this neighborhood, Company Z provides electricity

to how many houses?