Question

A chemist must dilute 62.8mL of 167.μM aqueous zinc oxalate ZnC2O4 solution until the concentration falls to 57.0μM . He'll do this by adding distilled water to the solution until it reaches a certain final volume.

Answer 1

184 mL.

Step-by-step explanation:

The following data were obtained from the question:

Initial volume (V1) = 62.8 mL

Initial concentration (C1) = 167 μM

Final concentration (C2) = 57.0 μM

Final volume (V2) =?

To obtain the final volume of the solution, we shall apply the dilution formula as follow:

C1V1 = C2V2

167 × 62.8 = 57 × V2

10487.6 = 57 × V2

Divide both side by 57

V2 = 10487.6 / 57

V2 = 183.99 ≈ 184 mL

Therefore, chemist must add distilled water to the solution until it reaches a volume of 184 mL.