Question

A gardener fills a 2 1/2 cubic foot wheelbarrow 2/3 of the way without soil weight 75.25 pounds. What is the weight of the soil un wheelbarrow?​

Answer 1

Volume of wheelbarrow , V = 2 1/2 ft³ = 5/2 ft³.

Volume of soil in wheelbarrow ,
`v = (5)/(3)\ ft^3` .

Mass of soil in wheelbarrow , m = 75.25 pounds.

Now, volume left ,
`v'=(5)/(6)\ ft^3` .

Let, mass of soil un wheelbarrow is x.

`x=((5)/(6)* 75.25)/((5)/(3))\\\\x=37.625\ pounds`

Hence, this is the required solution.