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Solve the exponential equation 16^(x+1)=1/32

1 Answer

8 votes

Answer:

x = -9/4

Explanation:

Focus on 16^(x+1)=1/32

Note that both 16 and 32 are powers of 2. To remove exponentiation from this equation, take the log to the base 2 of both sides:

(x + 1)(4) = -5 (Note: 16 = 2^4 and 32 = 2^5)

Then x + 1 = -5/4, so that x must be -9/4

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