Question

The average atomic mass of molybdenum (Mo) is 95.94 amu. Which of the following isotopes must have the highest percent abundance?

Answer 1

The two isotopes of Molybdenum have equal natural abundance

Step-by-step explanation:

`((95.94 + x))/(2)` = 95.95 amu

x = (95.95 * 2) - 95.94

= 95.96 amu is isotope B, while 95.94amu is isotope A

Using the formula x + (1 - x) = 1

95.96x + 95.94 (1-x) = 95.95

95.96x + 95.94 - 95.94x = 95.95

0.02x = 0.01

x = 0.5

∴ Isotope A and B have equal abundance since 0.5 = 50% abundance.

i hope this was helpful.