Answer: 21, 23, 25
Explanation:
Let the integers be y, y+2 and y+4.
From the question, we are informed that the result of adding the smallest integer to four times the largest integer is 121. This can be mathematically expressed as:
y + 4(y+4) = 121
y + 4y + 16 = 121
5y + 16 = 121
5y = 121-16
5y = 105
y = 105/5
y = 21
Since y = 21,
y + 2 = 21 + 2 = 23
y + 4 = 21 + 4 = 25
The integers are 21,23 and 25