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Find the remainder when x³-2x²+4x-2 is divided by (x-1/2)​

User MattSlay
by
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2 Answers

30 votes
30 votes

Answer:

-3/8

Explanation:

Let's assume x - 1/2 is a zero of the polynomial :

  • Substitute x = 1/2 (the zero) in the equation
  • x³ - 2x² + 4x - 2
  • (1/2)³ - 2(1/2)² + 4(1/2) - 2
  • 1/8 - 2(1/4) + 2 - 2
  • 1/8 - 1/2
  • -3/8

-3/8 is the remainder.

User Mohammad Dohadwala
by
2.5k points
25 votes
25 votes

Answer:


\sf \bf {remainder}: -(3)/(8)

In order to find remainder:

Follow this short technique:

Set the divisor which is x-½ to zero.

x - 1/2 = 0

x = 1/2

Then insert this following into dividend.

  • x³ -2x² + 4x - 2

insert x = ½

  • (½)³ - 2(½)² + 4(½) -2

simplify

  • -3/8
User ZeroKelvin
by
2.4k points