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24 votes
9x^2+4y÷z when x=2/3, y=3, and z=6

2 Answers

10 votes

Answer:

6

Explanation:


\text{From the question...}\\9x^2 + 4y / z\\x = (2)/(3)\\y = 3\\z = 6\\\\\text{Substitute in values}\\9((2)/(3))^2 + 4(3) / (6)\\\\\text{Following the rules of BODMAS or PEMDAS}\\9((4)/(9)) + 12 / 6\\4 + 2\\6

User Ares Draguna
by
8.7k points
9 votes
Answer: 6

Explanation: Fill in the variables with numbers.
9(2/3)^2 + 4(3) divide 6

Use PEMDAS.
User Button
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